Base | Representation |
---|---|
bin | 110101001001000111… |
… | …0110100111011111001 |
3 | 101220120101122012001100 |
4 | 1222102032310323321 |
5 | 3332210330310243 |
6 | 124232133242013 |
7 | 11150030221155 |
oct | 1522216647371 |
9 | 356511565040 |
10 | 114122510073 |
11 | 444431aaa30 |
12 | 1a14b493309 |
13 | a9b9613b90 |
14 | 5748908065 |
15 | 2e7debc0d3 |
hex | 1a923b4ef9 |
114122510073 has 24 divisors (see below), whose sum is σ = 193662443520. Its totient is φ = 63844760160.
The previous prime is 114122510041. The next prime is 114122510077. The reversal of 114122510073 is 370015221411.
114122510073 is a `hidden beast` number, since 1 + 141 + 2 + 2 + 510 + 0 + 7 + 3 = 666.
It is not a de Polignac number, because 114122510073 - 25 = 114122510041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114122510077) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 44335353 + ... + 44337926.
It is an arithmetic number, because the mean of its divisors is an integer number (8069268480).
Almost surely, 2114122510073 is an apocalyptic number.
114122510073 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
114122510073 is a deficient number, since it is larger than the sum of its proper divisors (79539933447).
114122510073 is a wasteful number, since it uses less digits than its factorization.
114122510073 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88673309 (or 88673306 counting only the distinct ones).
The product of its (nonzero) digits is 1680, while the sum is 27.
Adding to 114122510073 its reverse (370015221411), we get a palindrome (484137731484).
The spelling of 114122510073 in words is "one hundred fourteen billion, one hundred twenty-two million, five hundred ten thousand, seventy-three".
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