114123103000969 has 2 divisors, whose sum is σ = 114123103000970. Its totient is φ = 114123103000968.

The previous prime is 114123103000961. The next prime is 114123103001129. The reversal of 114123103000969 is 969000301321411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109393295765625 + 4729807235344 = 10459125^2 + 2174812^2 .

It is an emirp because it is prime and its reverse (969000301321411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114123103000969 - 2³ = 114123103000961 is a prime.

It is a super-3 number, since 3×114123103000969³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (114123103000961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061551500484 + 57061551500485.

It is an arithmetic number, because the mean of its divisors is an integer number (57061551500485).

Almost surely, 2^{114123103000969} is an apocalyptic number.

It is an amenable number.

114123103000969 is a deficient number, since it is larger than the sum of its proper divisors (1).

114123103000969 is an equidigital number, since it uses as much as digits as its factorization.

114123103000969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 40.

The spelling of 114123103000969 in words is "one hundred fourteen trillion, one hundred twenty-three billion, one hundred three million, nine hundred sixty-nine", and thus it is an aban number.