Base | Representation |
---|---|
bin | 11001111100101101101001… |
… | …101111101110111000111011 |
3 | 112222002002022111021222010101 |
4 | 121330231221233232320323 |
5 | 104424244110114030043 |
6 | 1042415313203300231 |
7 | 33016066001450521 |
oct | 3174555157567073 |
9 | 488062274258111 |
10 | 114123350142523 |
11 | 333aa493a69607 |
12 | 10971a5307a677 |
13 | 4b8aa2a3717b7 |
14 | 20278574d6311 |
15 | d2d92482d24d |
hex | 67cb69beee3b |
114123350142523 has 2 divisors, whose sum is σ = 114123350142524. Its totient is φ = 114123350142522.
The previous prime is 114123350142479. The next prime is 114123350142563. The reversal of 114123350142523 is 325241053321411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114123350142523 is a prime.
It is not a weakly prime, because it can be changed into another prime (114123350142563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061675071261 + 57061675071262.
It is an arithmetic number, because the mean of its divisors is an integer number (57061675071262).
Almost surely, 2114123350142523 is an apocalyptic number.
114123350142523 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123350142523 is an equidigital number, since it uses as much as digits as its factorization.
114123350142523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 114123350142523 in words is "one hundred fourteen trillion, one hundred twenty-three billion, three hundred fifty million, one hundred forty-two thousand, five hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •