Base | Representation |
---|---|
bin | 10000100110110111011… |
… | …100011010001100100111 |
3 | 11001002202020221121220221 |
4 | 100212313130122030213 |
5 | 122144231431330203 |
6 | 2232140311505211 |
7 | 145311043016314 |
oct | 20466734321447 |
9 | 4032666847827 |
10 | 1141244011303 |
11 | 3aaaa9546150 |
12 | 165220388207 |
13 | 838077c15a6 |
14 | 3d344d7dd0b |
15 | 1ea467b8abd |
hex | 109b771a327 |
1141244011303 has 8 divisors (see below), whose sum is σ = 1248560787600. Its totient is φ = 1034521788480.
The previous prime is 1141244011283. The next prime is 1141244011331. The reversal of 1141244011303 is 3031104421411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1141244011303 - 225 = 1141210456871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1141244011403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 148634350 + ... + 148642027.
It is an arithmetic number, because the mean of its divisors is an integer number (156070098450).
Almost surely, 21141244011303 is an apocalyptic number.
1141244011303 is a deficient number, since it is larger than the sum of its proper divisors (107316776297).
1141244011303 is a wasteful number, since it uses less digits than its factorization.
1141244011303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297276737.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1141244011303 its reverse (3031104421411), we get a palindrome (4172348432714).
The spelling of 1141244011303 in words is "one trillion, one hundred forty-one billion, two hundred forty-four million, eleven thousand, three hundred three".
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