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11412445153481 is a prime number
BaseRepresentation
bin1010011000010010101010…
…1111010100100011001001
31111102000111220222100102122
42212010222233110203021
52443440141424402411
640134445510341025
72255344013143541
oct246045257244311
944360456870378
1011412445153481
1136aaa99849319
12134398495a775
1364a25c1b7928
142b6518512321
1514bce59559db
hexa612abd48c9

11412445153481 has 2 divisors, whose sum is σ = 11412445153482. Its totient is φ = 11412445153480.

The previous prime is 11412445153441. The next prime is 11412445153513. The reversal of 11412445153481 is 18435154421411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6996210151225 + 4416235002256 = 2645035^2 + 2101484^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11412445153481 is a prime.

It is a super-2 number, since 2×114124451534812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11412445153441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706222576740 + 5706222576741.

It is an arithmetic number, because the mean of its divisors is an integer number (5706222576741).

Almost surely, 211412445153481 is an apocalyptic number.

It is an amenable number.

11412445153481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412445153481 is an equidigital number, since it uses as much as digits as its factorization.

11412445153481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 307200, while the sum is 44.

Adding to 11412445153481 its reverse (18435154421411), we get a palindrome (29847599574892).

The spelling of 11412445153481 in words is "eleven trillion, four hundred twelve billion, four hundred forty-five million, one hundred fifty-three thousand, four hundred eighty-one".