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11412504401 is a prime number
BaseRepresentation
bin10101010000011110…
…01111111101010001
31002110100122021220012
422220033033331101
5141333100120101
65124241324305
7552545454404
oct125017177521
932410567805
1011412504401
114927074521
122266036695
1310cb5266ac
147a39abd3b
1546bdc2bbb
hex2a83cff51

11412504401 has 2 divisors, whose sum is σ = 11412504402. Its totient is φ = 11412504400.

The previous prime is 11412504391. The next prime is 11412504409. The reversal of 11412504401 is 10440521411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11288850001 + 123654400 = 106249^2 + 11120^2 .

It is an emirp because it is prime and its reverse (10440521411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11412504401 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11412504409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706252200 + 5706252201.

It is an arithmetic number, because the mean of its divisors is an integer number (5706252201).

Almost surely, 211412504401 is an apocalyptic number.

It is an amenable number.

11412504401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412504401 is an equidigital number, since it uses as much as digits as its factorization.

11412504401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 640, while the sum is 23.

The spelling of 11412504401 in words is "eleven billion, four hundred twelve million, five hundred four thousand, four hundred one".