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114125221432553 is a prime number
BaseRepresentation
bin11001111100101111011001…
…010010001000110011101001
3112222002021010220110100110112
4121330233121102020303221
5104424311423141320203
61042420223011424105
733016163243243552
oct3174573122106351
9488067126410415
10114125221432553
11334002642954a1
12109722958b5035
134b8ac67c625c6
142027993c49329
15d2d9d3c696d8
hex67cbd9488ce9

114125221432553 has 2 divisors, whose sum is σ = 114125221432554. Its totient is φ = 114125221432552.

The previous prime is 114125221432511. The next prime is 114125221432693. The reversal of 114125221432553 is 355234122521411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85341438469849 + 28783782962704 = 9238043^2 + 5365052^2 .

It is a cyclic number.

It is not a de Polignac number, because 114125221432553 - 218 = 114125221170409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114125221432553.

It is not a weakly prime, because it can be changed into another prime (114125271432553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57062610716276 + 57062610716277.

It is an arithmetic number, because the mean of its divisors is an integer number (57062610716277).

Almost surely, 2114125221432553 is an apocalyptic number.

It is an amenable number.

114125221432553 is a deficient number, since it is larger than the sum of its proper divisors (1).

114125221432553 is an equidigital number, since it uses as much as digits as its factorization.

114125221432553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288000, while the sum is 41.

Adding to 114125221432553 its reverse (355234122521411), we get a palindrome (469359343953964).

The spelling of 114125221432553 in words is "one hundred fourteen trillion, one hundred twenty-five billion, two hundred twenty-one million, four hundred thirty-two thousand, five hundred fifty-three".