Base | Representation |
---|---|
bin | 10101010000100010… |
… | …01011101110000111 |
3 | 1002110101121001021112 |
4 | 22220101023232013 |
5 | 141333212330320 |
6 | 5124300235235 |
7 | 552552665345 |
oct | 125021135607 |
9 | 32411531245 |
10 | 11413011335 |
11 | 4927390380 |
12 | 226623bb1b |
13 | 10cb67335b |
14 | 7a3aa0995 |
15 | 46be72ec5 |
hex | 2a844bb87 |
11413011335 has 32 divisors (see below), whose sum is σ = 15505922880. Its totient is φ = 7988198400.
The previous prime is 11413011317. The next prime is 11413011349. The reversal of 11413011335 is 53311031411.
It is not a de Polignac number, because 11413011335 - 216 = 11412945799 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11413011335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 487805 + ... + 510665.
It is an arithmetic number, because the mean of its divisors is an integer number (484560090).
Almost surely, 211413011335 is an apocalyptic number.
11413011335 is a deficient number, since it is larger than the sum of its proper divisors (4092911545).
11413011335 is a wasteful number, since it uses less digits than its factorization.
11413011335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23219.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 11413011335 its reverse (53311031411), we get a palindrome (64724042746).
The spelling of 11413011335 in words is "eleven billion, four hundred thirteen million, eleven thousand, three hundred thirty-five".
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