1141303330035 has 64 divisors (see below), whose sum is σ = 2255199874560. Its totient is φ = 542918413440.

The previous prime is 1141303330033. The next prime is 1141303330081. The reversal of 1141303330035 is 5300333031411.

1141303330035 is a `hidden beast` number, since 11 + 41 + 303 + 3 + 300 + 3 + 5 = 666.

It is not a de Polignac number, because 1141303330035 - 2¹ = 1141303330033 is a prime.

It is a super-2 number, since 2×1141303330035² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1141303329990 and 1141303330008.

It is not an unprimeable number, because it can be changed into a prime (1141303330033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7171809 + ... + 7329218.

It is an arithmetic number, because the mean of its divisors is an integer number (35237498040).

Almost surely, 2^{1141303330035} is an apocalyptic number.

1141303330035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1141303330035 is a deficient number, since it is larger than the sum of its proper divisors (1113896544525).

1141303330035 is a wasteful number, since it uses less digits than its factorization.

1141303330035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14501105 (or 14501099 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 27.

Adding to 1141303330035 its reverse (5300333031411), we get a palindrome (6441636361446).

The spelling of 1141303330035 in words is "one trillion, one hundred forty-one billion, three hundred three million, three hundred thirty thousand, thirty-five".