Base | Representation |
---|---|
bin | 1010011000010101001111… |
… | …0000011110011110011111 |
3 | 1111102002021212212221100212 |
4 | 2212011103300132132133 |
5 | 2443443044112302033 |
6 | 40135042052243035 |
7 | 2255400040400300 |
oct | 246052360363637 |
9 | 44362255787325 |
10 | 11413133322143 |
11 | 3700312247653 |
12 | 1343b3731047b |
13 | 64a33b943a17 |
14 | 2b6581a8a7a7 |
15 | 14bd3608c748 |
hex | a6153c1e79f |
11413133322143 has 12 divisors (see below), whose sum is σ = 13276580377320. Its totient is φ = 9782627973552.
The previous prime is 11413133322127. The next prime is 11413133322197. The reversal of 11413133322143 is 34122333131411.
It is not a de Polignac number, because 11413133322143 - 24 = 11413133322127 is a prime.
It is a super-2 number, since 2×114131333221432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11413133324143) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9111893 + ... + 10288481.
It is an arithmetic number, because the mean of its divisors is an integer number (1106381698110).
Almost surely, 211413133322143 is an apocalyptic number.
11413133322143 is a deficient number, since it is larger than the sum of its proper divisors (1863447055177).
11413133322143 is a wasteful number, since it uses less digits than its factorization.
11413133322143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1374566 (or 1374559 counting only the distinct ones).
The product of its digits is 15552, while the sum is 32.
Adding to 11413133322143 its reverse (34122333131411), we get a palindrome (45535466453554).
The spelling of 11413133322143 in words is "eleven trillion, four hundred thirteen billion, one hundred thirty-three million, three hundred twenty-two thousand, one hundred forty-three".
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