Base | Representation |
---|---|
bin | 10101010000100011… |
… | …01011101000010001 |
3 | 1002110101211200120012 |
4 | 22220101223220101 |
5 | 141333231021113 |
6 | 5124303124305 |
7 | 552554051366 |
oct | 125021535021 |
9 | 32411750505 |
10 | 11413142033 |
11 | 492746a597 |
12 | 22662a3695 |
13 | 10cb6ba9a7 |
14 | 7a3ad646d |
15 | 46be9baa8 |
hex | 2a846ba11 |
11413142033 has 2 divisors, whose sum is σ = 11413142034. Its totient is φ = 11413142032.
The previous prime is 11413141849. The next prime is 11413142047. The reversal of 11413142033 is 33024131411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9535913104 + 1877228929 = 97652^2 + 43327^2 .
It is a cyclic number.
It is not a de Polignac number, because 11413142033 - 218 = 11412879889 is a prime.
It is a super-2 number, since 2×114131420332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11413142233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706571016 + 5706571017.
It is an arithmetic number, because the mean of its divisors is an integer number (5706571017).
Almost surely, 211413142033 is an apocalyptic number.
It is an amenable number.
11413142033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413142033 is an equidigital number, since it uses as much as digits as its factorization.
11413142033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 11413142033 its reverse (33024131411), we get a palindrome (44437273444).
The spelling of 11413142033 in words is "eleven billion, four hundred thirteen million, one hundred forty-two thousand, thirty-three".
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