Search a number
-
+
11413210044107 is a prime number
BaseRepresentation
bin1010011000010101100001…
…0101001001011011001011
31111102002111020020211010002
42212011120111021123023
52443443223232402412
640135053432513215
72255401661461424
oct246053025113313
944362436224102
1011413210044107
113700351589a33
121343b58b4b80b
1364a3517c7031
142b658bd3c64b
1514bd3cb94dc2
hexa61585496cb

11413210044107 has 2 divisors, whose sum is σ = 11413210044108. Its totient is φ = 11413210044106.

The previous prime is 11413210044059. The next prime is 11413210044179. The reversal of 11413210044107 is 70144001231411.

It is a weak prime.

It is an emirp because it is prime and its reverse (70144001231411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11413210044107 - 210 = 11413210043083 is a prime.

It is a super-2 number, since 2×114132100441072 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11413210044107.

It is not a weakly prime, because it can be changed into another prime (11413210046107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706605022053 + 5706605022054.

It is an arithmetic number, because the mean of its divisors is an integer number (5706605022054).

Almost surely, 211413210044107 is an apocalyptic number.

11413210044107 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413210044107 is an equidigital number, since it uses as much as digits as its factorization.

11413210044107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 11413210044107 its reverse (70144001231411), we get a palindrome (81557211275518).

The spelling of 11413210044107 in words is "eleven trillion, four hundred thirteen billion, two hundred ten million, forty-four thousand, one hundred seven".