Base | Representation |
---|---|
bin | 10000100110111100000… |
… | …011010010110010100011 |
3 | 11001002221122101222112011 |
4 | 100212330003102302203 |
5 | 122144411224012233 |
6 | 2232152112413351 |
7 | 145313002045063 |
oct | 20467403226243 |
9 | 4032848358464 |
10 | 1141321313443 |
11 | 400039144413 |
12 | 165242247257 |
13 | 8381a8189bc |
14 | 3d3513433a3 |
15 | 1ea4d4880cd |
hex | 109bc0d2ca3 |
1141321313443 has 2 divisors, whose sum is σ = 1141321313444. Its totient is φ = 1141321313442.
The previous prime is 1141321313389. The next prime is 1141321313471. The reversal of 1141321313443 is 3443131231411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1141321313443 - 29 = 1141321312931 is a prime.
It is a super-2 number, since 2×11413213134432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1145321313443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570660656721 + 570660656722.
It is an arithmetic number, because the mean of its divisors is an integer number (570660656722).
Almost surely, 21141321313443 is an apocalyptic number.
1141321313443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141321313443 is an equidigital number, since it uses as much as digits as its factorization.
1141321313443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 31.
Adding to 1141321313443 its reverse (3443131231411), we get a palindrome (4584452544854).
The spelling of 1141321313443 in words is "one trillion, one hundred forty-one billion, three hundred twenty-one million, three hundred thirteen thousand, four hundred forty-three".
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