Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11111101001101001 |
3 | 1002110101222212001112 |
4 | 22220101333221221 |
5 | 141333241132131 |
6 | 5124305000105 |
7 | 552554542442 |
oct | 125021775151 |
9 | 32411885045 |
10 | 11413224041 |
11 | 492751616a |
12 | 2266323035 |
13 | 10cb71910b |
14 | 7a3b182c9 |
15 | 46beb602b |
hex | 2a847fa69 |
11413224041 has 2 divisors, whose sum is σ = 11413224042. Its totient is φ = 11413224040.
The previous prime is 11413224029. The next prime is 11413224047. The reversal of 11413224041 is 14042231411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6036668416 + 5376555625 = 77696^2 + 73325^2 .
It is a cyclic number.
It is not a de Polignac number, because 11413224041 - 230 = 10339482217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11413223998 and 11413224016.
It is not a weakly prime, because it can be changed into another prime (11413224047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706612020 + 5706612021.
It is an arithmetic number, because the mean of its divisors is an integer number (5706612021).
Almost surely, 211413224041 is an apocalyptic number.
It is an amenable number.
11413224041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413224041 is an equidigital number, since it uses as much as digits as its factorization.
11413224041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11413224041 its reverse (14042231411), we get a palindrome (25455455452).
The spelling of 11413224041 in words is "eleven billion, four hundred thirteen million, two hundred twenty-four thousand, forty-one".
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