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114133000040 = 2352853325001
BaseRepresentation
bin110101001001011011…
…0110101111101101000
3101220121010101010120122
41222102312311331220
53332221022000130
6124233150142412
711150215331153
oct1522266657550
9356533333518
10114133000040
1144449115224
121a152ab1a08
13a9bb847767
14574a078c9a
152e7ed902e5
hex1a92db5f68

114133000040 has 16 divisors (see below), whose sum is σ = 256799250180. Its totient is φ = 45653200000.

The previous prime is 114132999991. The next prime is 114133000063. The reversal of 114133000040 is 40000331411.

It can be written as a sum of positive squares in 2 ways, for example, as 93534435556 + 20598564484 = 305834^2 + 143522^2 .

It is a junction number, because it is equal to n+sod(n) for n = 114132999982 and 114133000018.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1426662461 + ... + 1426662540.

Almost surely, 2114133000040 is an apocalyptic number.

114133000040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

114133000040 is an abundant number, since it is smaller than the sum of its proper divisors (142666250140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114133000040 is a wasteful number, since it uses less digits than its factorization.

114133000040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2853325012 (or 2853325008 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 114133000040 its reverse (40000331411), we get a palindrome (154133331451).

The spelling of 114133000040 in words is "one hundred fourteen billion, one hundred thirty-three million, forty", and thus it is an aban number.

Divisors: 1 2 4 5 8 10 20 40 2853325001 5706650002 11413300004 14266625005 22826600008 28533250010 57066500020 114133000040