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114133021214053 = 417180513486971
BaseRepresentation
bin11001111100110110101010…
…001011111100010101100101
3112222010000021111010022012211
4121330312222023330111211
5104424423411412322203
61042423553000043421
733016560443266402
oct3174665213742545
9488100244108184
10114133021214053
11334035a7040806
12109738b1a63571
134b8b90bb72b2a
1420280d3ab52a9
15d2dcdd8b5c6d
hex67cdaa2fc565

114133021214053 has 16 divisors (see below), whose sum is σ = 118565184350592. Its totient is φ = 109779400192000.

The previous prime is 114133021213997. The next prime is 114133021214099. The reversal of 114133021214053 is 350412120331411.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 114133021214053 - 233 = 114124431279461 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114133021214153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 234129858 + ... + 234616828.

It is an arithmetic number, because the mean of its divisors is an integer number (7410324021912).

Almost surely, 2114133021214053 is an apocalyptic number.

It is an amenable number.

114133021214053 is a deficient number, since it is larger than the sum of its proper divisors (4432163136539).

114133021214053 is an equidigital number, since it uses as much as digits as its factorization.

114133021214053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 567596.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 114133021214053 its reverse (350412120331411), we get a palindrome (464545141545464).

The spelling of 114133021214053 in words is "one hundred fourteen trillion, one hundred thirty-three billion, twenty-one million, two hundred fourteen thousand, fifty-three".

Divisors: 1 41 71 2911 80513 486971 3301033 5716423 19965811 34574941 234373343 1417572581 39207496123 1607507341043 2783732224733 114133021214053