Base | Representation |
---|---|
bin | 10101010000100100… |
… | …11110110000010001 |
3 | 1002110102020022211001 |
4 | 22220102132300101 |
5 | 141333304221231 |
6 | 5124311422001 |
7 | 552555613042 |
oct | 125022366021 |
9 | 32412208731 |
10 | 11413351441 |
11 | 49275a2958 |
12 | 2266384901 |
13 | 10cb7620bb |
14 | 7a3b4c8c9 |
15 | 46beddb61 |
hex | 2a849ec11 |
11413351441 has 2 divisors, whose sum is σ = 11413351442. Its totient is φ = 11413351440.
The previous prime is 11413351427. The next prime is 11413351457. The reversal of 11413351441 is 14415331411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5790601216 + 5622750225 = 76096^2 + 74985^2 .
It is a cyclic number.
It is not a de Polignac number, because 11413351441 - 211 = 11413349393 is a prime.
It is a super-2 number, since 2×114133514412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11413331441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706675720 + 5706675721.
It is an arithmetic number, because the mean of its divisors is an integer number (5706675721).
Almost surely, 211413351441 is an apocalyptic number.
It is an amenable number.
11413351441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413351441 is an equidigital number, since it uses as much as digits as its factorization.
11413351441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2880, while the sum is 28.
Adding to 11413351441 its reverse (14415331411), we get a palindrome (25828682852).
The spelling of 11413351441 in words is "eleven billion, four hundred thirteen million, three hundred fifty-one thousand, four hundred forty-one".
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