Base | Representation |
---|---|
bin | 1010011000010110010100… |
… | …0001111110111000100011 |
3 | 1111102010001002012101210002 |
4 | 2212011211001332320203 |
5 | 2443444142304432003 |
6 | 40135130523530215 |
7 | 2255410156563545 |
oct | 246054501767043 |
9 | 44363032171702 |
10 | 11413423124003 |
11 | 370045089601a |
12 | 1343bb838996b |
13 | 64a3869b0a04 |
14 | 2b65ac367695 |
15 | 14bd51734a88 |
hex | a616507ee23 |
11413423124003 has 2 divisors, whose sum is σ = 11413423124004. Its totient is φ = 11413423124002.
The previous prime is 11413423123969. The next prime is 11413423124011. The reversal of 11413423124003 is 30042132431411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11413423124003 - 26 = 11413423123939 is a prime.
It is not a weakly prime, because it can be changed into another prime (11413423124063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706711562001 + 5706711562002.
It is an arithmetic number, because the mean of its divisors is an integer number (5706711562002).
Almost surely, 211413423124003 is an apocalyptic number.
11413423124003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413423124003 is an equidigital number, since it uses as much as digits as its factorization.
11413423124003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11413423124003 its reverse (30042132431411), we get a palindrome (41455555555414).
The spelling of 11413423124003 in words is "eleven trillion, four hundred thirteen billion, four hundred twenty-three million, one hundred twenty-four thousand, three".
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