Base | Representation |
---|---|
bin | 11001111100111000111000… |
… | …111000000111000110001011 |
3 | 112222010020110022202012202021 |
4 | 121330320320320013012023 |
5 | 104424443312240012011 |
6 | 1042425030314345311 |
7 | 33020003662415314 |
oct | 3174707070070613 |
9 | 488106408665667 |
10 | 114135415157131 |
11 | 33404615396665 |
12 | 1097425b72b237 |
13 | 4b8bc00b1a8b4 |
14 | 202827d9d960b |
15 | d2ddcdb42471 |
hex | 67ce38e0718b |
114135415157131 has 2 divisors, whose sum is σ = 114135415157132. Its totient is φ = 114135415157130.
The previous prime is 114135415157077. The next prime is 114135415157209. The reversal of 114135415157131 is 131751514531411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114135415157131 - 29 = 114135415156619 is a prime.
It is a super-2 number, since 2×1141354151571312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114135415152131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067707578565 + 57067707578566.
It is an arithmetic number, because the mean of its divisors is an integer number (57067707578566).
Almost surely, 2114135415157131 is an apocalyptic number.
114135415157131 is a deficient number, since it is larger than the sum of its proper divisors (1).
114135415157131 is an equidigital number, since it uses as much as digits as its factorization.
114135415157131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 126000, while the sum is 43.
Adding to 114135415157131 its reverse (131751514531411), we get a palindrome (245886929688542).
The spelling of 114135415157131 in words is "one hundred fourteen trillion, one hundred thirty-five billion, four hundred fifteen million, one hundred fifty-seven thousand, one hundred thirty-one".
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