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114140313434301 = 371113735910046437
BaseRepresentation
bin11001111100111101011100…
…110101100011100010111101
3112222010201002200201110211020
4121330331130311203202331
5104430033330214344201
61042431200333414353
733020236241163630
oct3174753465434275
9488121080643736
10114140313434301
11334066a9335810
12109751a803a3b9
134b8c50188175b
1420285c637bc17
15d2e0b8ba3a36
hex67cf5cd638bd

114140313434301 has 64 divisors (see below), whose sum is σ = 191657103298560. Its totient is φ = 58696905116160.

The previous prime is 114140313434269. The next prime is 114140313434317. The reversal of 114140313434301 is 103434313041411.

It is not a de Polignac number, because 114140313434301 - 25 = 114140313434269 is a prime.

It is a super-3 number, since 3×1141403134343013 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114140313434321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6338055 + ... + 16384491.

It is an arithmetic number, because the mean of its divisors is an integer number (2994642239040).

Almost surely, 2114140313434301 is an apocalyptic number.

114140313434301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

114140313434301 is a deficient number, since it is larger than the sum of its proper divisors (77516789864259).

114140313434301 is a wasteful number, since it uses less digits than its factorization.

114140313434301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10046954.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 114140313434301 its reverse (103434313041411), we get a palindrome (217574626475712).

The spelling of 114140313434301 in words is "one hundred fourteen trillion, one hundred forty billion, three hundred thirteen million, four hundred thirty-four thousand, three hundred one".

Divisors: 1 3 7 11 21 33 77 137 231 359 411 959 1077 1507 2513 2877 3949 4521 7539 10549 11847 27643 31647 49183 82929 147549 344281 541013 1032843 1623039 3787091 10046437 11361273 30139311 70325059 110510807 210975177 331532421 773575649 1376361869 2320726947 3606670883 4129085607 9634533083 10820012649 15139980559 25246696181 28903599249 39673379713 45419941677 75740088543 105979863913 119020139139 277713657991 317939591739 494113910971 833140973973 1482341732913 3458797376797 5435253020681 10376392130391 16305759062043 38046771144767 114140313434301