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1141411311137 is a prime number
BaseRepresentation
bin10000100111000001011…
…010100110111000100001
311001010011220202100011002
4100213001122212320201
5122200102243424022
62232205045401345
7145315144031036
oct20470132467041
94033156670132
101141411311137
11400084a23a79
12165268409255
1383833369886
143d35d28d38d
151ea56314092
hex109c16a6e21

1141411311137 has 2 divisors, whose sum is σ = 1141411311138. Its totient is φ = 1141411311136.

The previous prime is 1141411311121. The next prime is 1141411311149. The reversal of 1141411311137 is 7311131141411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 929920776976 + 211490534161 = 964324^2 + 459881^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141411311137 - 24 = 1141411311121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1141411311167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570705655568 + 570705655569.

It is an arithmetic number, because the mean of its divisors is an integer number (570705655569).

Almost surely, 21141411311137 is an apocalyptic number.

It is an amenable number.

1141411311137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141411311137 is an equidigital number, since it uses as much as digits as its factorization.

1141411311137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1008, while the sum is 29.

Adding to 1141411311137 its reverse (7311131141411), we get a palindrome (8452542452548).

The spelling of 1141411311137 in words is "one trillion, one hundred forty-one billion, four hundred eleven million, three hundred eleven thousand, one hundred thirty-seven".