1141414003 has 2 divisors, whose sum is σ = 1141414004. Its totient is φ = 1141414002.

The previous prime is 1141413997. The next prime is 1141414033. The reversal of 1141414003 is 3004141411.

It is a weak prime.

It is an emirp because it is prime and its reverse (3004141411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141414003 - 2⁵ = 1141413971 is a prime.

It is not a weakly prime, because it can be changed into another prime (1141414033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570707001 + 570707002.

It is an arithmetic number, because the mean of its divisors is an integer number (570707002).

Almost surely, 2^1141414003 is an apocalyptic number.

1141414003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141414003 is an equidigital number, since it uses as much as digits as its factorization.

1141414003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1141414003 is about 33784.8191204274. The cubic root of 1141414003 is about 1045.0756576252.

Adding to 1141414003 its reverse (3004141411), we get a palindrome (4145555414).

The spelling of 1141414003 in words is "one billion, one hundred forty-one million, four hundred fourteen thousand, three".