Base | Representation |
---|---|
bin | 110101001001101011… |
… | …1010100001101010011 |
3 | 101220121201101121112002 |
4 | 1222103113110031103 |
5 | 3332230211400111 |
6 | 124234052424215 |
7 | 11150350564004 |
oct | 1522327241523 |
9 | 356551347462 |
10 | 114141512531 |
11 | 444529a9842 |
12 | 1a15591806b |
13 | a9c0538237 |
14 | 574b2531ab |
15 | 2e809c263b |
hex | 1a935d4353 |
114141512531 has 2 divisors, whose sum is σ = 114141512532. Its totient is φ = 114141512530.
The previous prime is 114141512521. The next prime is 114141512561. The reversal of 114141512531 is 135215141411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114141512531 - 210 = 114141511507 is a prime.
It is a super-2 number, since 2×1141415125312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114141512494 and 114141512503.
It is not a weakly prime, because it can be changed into another prime (114141512501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57070756265 + 57070756266.
It is an arithmetic number, because the mean of its divisors is an integer number (57070756266).
Almost surely, 2114141512531 is an apocalyptic number.
114141512531 is a deficient number, since it is larger than the sum of its proper divisors (1).
114141512531 is an equidigital number, since it uses as much as digits as its factorization.
114141512531 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2400, while the sum is 29.
Adding to 114141512531 its reverse (135215141411), we get a palindrome (249356653942).
The spelling of 114141512531 in words is "one hundred fourteen billion, one hundred forty-one million, five hundred twelve thousand, five hundred thirty-one".
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