Base | Representation |
---|---|
bin | 1010011000011010000100… |
… | …1000010111010111100010 |
3 | 1111102012122100111122201212 |
4 | 2212012201020113113202 |
5 | 2444003223421230424 |
6 | 40135414543230122 |
7 | 2255444152210526 |
oct | 246064110272742 |
9 | 44365570448655 |
10 | 11414431430114 |
11 | 3700918a72359 |
12 | 1344239ba8342 |
13 | 64a4b786874b |
14 | 2b6666237d86 |
15 | 14bdb000710e |
hex | a61a12175e2 |
11414431430114 has 4 divisors (see below), whose sum is σ = 17121647145174. Its totient is φ = 5707215715056.
The previous prime is 11414431430111. The next prime is 11414431430141. The reversal of 11414431430114 is 41103413441411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8184205248025 + 3230226182089 = 2860805^2 + 1797283^2 .
It is not an unprimeable number, because it can be changed into a prime (11414431430111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2853607857527 + ... + 2853607857530.
Almost surely, 211414431430114 is an apocalyptic number.
11414431430114 is a deficient number, since it is larger than the sum of its proper divisors (5707215715060).
11414431430114 is an equidigital number, since it uses as much as digits as its factorization.
11414431430114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5707215715059.
The product of its (nonzero) digits is 9216, while the sum is 32.
Adding to 11414431430114 its reverse (41103413441411), we get a palindrome (52517844871525).
The spelling of 11414431430114 in words is "eleven trillion, four hundred fourteen billion, four hundred thirty-one million, four hundred thirty thousand, one hundred fourteen".
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