Base | Representation |
---|---|
bin | 10101010000110010… |
… | …10001000010000001 |
3 | 1002110112120200212112 |
4 | 22220121101002001 |
5 | 141334233131431 |
6 | 5124413505105 |
7 | 552610002044 |
oct | 125031210201 |
9 | 32415520775 |
10 | 11415130241 |
11 | 49285a8339 |
12 | 2266aa2195 |
13 | 10cbc35948 |
14 | 7a4092c5b |
15 | 46c240c2b |
hex | 2a8651081 |
11415130241 has 2 divisors, whose sum is σ = 11415130242. Its totient is φ = 11415130240.
The previous prime is 11415130229. The next prime is 11415130247. The reversal of 11415130241 is 14203151411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10083172225 + 1331958016 = 100415^2 + 36496^2 .
It is an emirp because it is prime and its reverse (14203151411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11415130241 - 210 = 11415129217 is a prime.
It is not a weakly prime, because it can be changed into another prime (11415130247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707565120 + 5707565121.
It is an arithmetic number, because the mean of its divisors is an integer number (5707565121).
Almost surely, 211415130241 is an apocalyptic number.
It is an amenable number.
11415130241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11415130241 is an equidigital number, since it uses as much as digits as its factorization.
11415130241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 11415130241 its reverse (14203151411), we get a palindrome (25618281652).
The spelling of 11415130241 in words is "eleven billion, four hundred fifteen million, one hundred thirty thousand, two hundred forty-one".
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