Base | Representation |
---|---|
bin | 10000100111000111100… |
… | …011000110100101000110 |
3 | 11001010110002100201002002 |
4 | 100213013203012211012 |
5 | 122200310113421124 |
6 | 2232223202545302 |
7 | 145320533421506 |
oct | 20470743064506 |
9 | 4033402321062 |
10 | 1141514201414 |
11 | 400128009a64 |
12 | 165296968232 |
13 | 8384b782ab2 |
14 | 3d36cbd3a06 |
15 | 1ea6038a0ae |
hex | 109c78c6946 |
1141514201414 has 4 divisors (see below), whose sum is σ = 1712271302124. Its totient is φ = 570757100706.
The previous prime is 1141514201369. The next prime is 1141514201437. The reversal of 1141514201414 is 4141024151411.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285378550352 + ... + 285378550355.
It is an arithmetic number, because the mean of its divisors is an integer number (428067825531).
Almost surely, 21141514201414 is an apocalyptic number.
1141514201414 is a deficient number, since it is larger than the sum of its proper divisors (570757100710).
1141514201414 is an equidigital number, since it uses as much as digits as its factorization.
1141514201414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 570757100709.
The product of its (nonzero) digits is 2560, while the sum is 29.
Adding to 1141514201414 its reverse (4141024151411), we get a palindrome (5282538352825).
The spelling of 1141514201414 in words is "one trillion, one hundred forty-one billion, five hundred fourteen million, two hundred one thousand, four hundred fourteen".
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