Base | Representation |
---|---|
bin | 10000100111001000100… |
… | …101001101001100111011 |
3 | 11001010111021222002111011 |
4 | 100213020211031030323 |
5 | 122200324032430133 |
6 | 2232225022214351 |
7 | 145321133623342 |
oct | 20471045151473 |
9 | 4033437862434 |
10 | 1141531530043 |
11 | 400136875243 |
12 | 1652a07243b7 |
13 | 8385223c318 |
14 | 3d371224b59 |
15 | 1ea61b5e6cd |
hex | 109c894d33b |
1141531530043 has 2 divisors, whose sum is σ = 1141531530044. Its totient is φ = 1141531530042.
The previous prime is 1141531530001. The next prime is 1141531530059. The reversal of 1141531530043 is 3400351351411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1141531530043 is a prime.
It is a super-2 number, since 2×11415315300432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1141531529987 and 1141531530014.
It is not a weakly prime, because it can be changed into another prime (1141531530143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570765765021 + 570765765022.
It is an arithmetic number, because the mean of its divisors is an integer number (570765765022).
Almost surely, 21141531530043 is an apocalyptic number.
1141531530043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141531530043 is an equidigital number, since it uses as much as digits as its factorization.
1141531530043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1141531530043 its reverse (3400351351411), we get a palindrome (4541882881454).
The spelling of 1141531530043 in words is "one trillion, one hundred forty-one billion, five hundred thirty-one million, five hundred thirty thousand, forty-three".
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