Base | Representation |
---|---|
bin | 11001111101001011010000… |
… | …000010101011000100101011 |
3 | 112222012010100100212122221121 |
4 | 121331023100002223010223 |
5 | 104430304202033422411 |
6 | 1042442050540520111 |
7 | 33021302365552012 |
oct | 3175132002530453 |
9 | 488163310778847 |
10 | 114155131154731 |
11 | 33411a12578457 |
12 | 10978042550037 |
13 | 4b90a23709174 |
14 | 20291d02b3a79 |
15 | d2e6849ae571 |
hex | 67d2d00ab12b |
114155131154731 has 2 divisors, whose sum is σ = 114155131154732. Its totient is φ = 114155131154730.
The previous prime is 114155131154641. The next prime is 114155131154749. The reversal of 114155131154731 is 137451131551411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114155131154731 - 211 = 114155131152683 is a prime.
It is a super-2 number, since 2×1141551311547312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114155131454731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57077565577365 + 57077565577366.
It is an arithmetic number, because the mean of its divisors is an integer number (57077565577366).
Almost surely, 2114155131154731 is an apocalyptic number.
114155131154731 is a deficient number, since it is larger than the sum of its proper divisors (1).
114155131154731 is an equidigital number, since it uses as much as digits as its factorization.
114155131154731 is an evil number, because the sum of its binary digits is even.
The product of its digits is 126000, while the sum is 43.
The spelling of 114155131154731 in words is "one hundred fourteen trillion, one hundred fifty-five billion, one hundred thirty-one million, one hundred fifty-four thousand, seven hundred thirty-one".
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