11420131131307 has 2 divisors, whose sum is σ = 11420131131308. Its totient is φ = 11420131131306.

The previous prime is 11420131131263. The next prime is 11420131131319. The reversal of 11420131131307 is 70313113102411.

It is a strong prime.

It is an emirp because it is prime and its reverse (70313113102411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11420131131307 - 2³⁹ = 10870375317419 is a prime.

It is not a weakly prime, because it can be changed into another prime (11420131131377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710065565653 + 5710065565654.

It is an arithmetic number, because the mean of its divisors is an integer number (5710065565654).

Almost surely, 2^{11420131131307} is an apocalyptic number.

11420131131307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11420131131307 is an equidigital number, since it uses as much as digits as its factorization.

11420131131307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 11420131131307 its reverse (70313113102411), we get a palindrome (81733244233718).

The spelling of 11420131131307 in words is "eleven trillion, four hundred twenty billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred seven".