Base | Representation |
---|---|
bin | 11001111101110110010010… |
… | …011000111000100100110011 |
3 | 112222100112121211122212122201 |
4 | 121331312102120320210303 |
5 | 104432033321401230232 |
6 | 1042515212203244031 |
7 | 33024526462452553 |
oct | 3175662230704463 |
9 | 488315554585581 |
10 | 114201341430067 |
11 | 3342a576018251 |
12 | 10984b9a219617 |
13 | 4b951a929b758 |
14 | 202b535589163 |
15 | d3098b7b7be7 |
hex | 67dd92638933 |
114201341430067 has 2 divisors, whose sum is σ = 114201341430068. Its totient is φ = 114201341430066.
The previous prime is 114201341430037. The next prime is 114201341430079. The reversal of 114201341430067 is 760034143102411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114201341430067 - 211 = 114201341428019 is a prime.
It is not a weakly prime, because it can be changed into another prime (114201341430037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57100670715033 + 57100670715034.
It is an arithmetic number, because the mean of its divisors is an integer number (57100670715034).
Almost surely, 2114201341430067 is an apocalyptic number.
114201341430067 is a deficient number, since it is larger than the sum of its proper divisors (1).
114201341430067 is an equidigital number, since it uses as much as digits as its factorization.
114201341430067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 37.
Adding to 114201341430067 its reverse (760034143102411), we get a palindrome (874235484532478).
The spelling of 114201341430067 in words is "one hundred fourteen trillion, two hundred one billion, three hundred forty-one million, four hundred thirty thousand, sixty-seven".
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