Base | Representation |
---|---|
bin | 110101001011100010… |
… | …0001101100010010110 |
3 | 101220210001020122210211 |
4 | 1222113010031202112 |
5 | 3332342111111314 |
6 | 124244151440034 |
7 | 11152033460626 |
oct | 1522704154226 |
9 | 356701218724 |
10 | 114203613334 |
11 | 44484a65018 |
12 | 1a17268601a |
13 | aa0036c485 |
14 | 57555ba886 |
15 | 2e8618c9c4 |
hex | 1a9710d896 |
114203613334 has 4 divisors (see below), whose sum is σ = 171305420004. Its totient is φ = 57101806666.
The previous prime is 114203613313. The next prime is 114203613343. The reversal of 114203613334 is 433316302411.
114203613334 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 433316302411 = 89 ⋅4868722499.
It is a junction number, because it is equal to n+sod(n) for n = 114203613296 and 114203613305.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28550903332 + ... + 28550903335.
It is an arithmetic number, because the mean of its divisors is an integer number (42826355001).
Almost surely, 2114203613334 is an apocalyptic number.
114203613334 is a deficient number, since it is larger than the sum of its proper divisors (57101806670).
114203613334 is an equidigital number, since it uses as much as digits as its factorization.
114203613334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57101806669.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 114203613334 its reverse (433316302411), we get a palindrome (547519915745).
The spelling of 114203613334 in words is "one hundred fourteen billion, two hundred three million, six hundred thirteen thousand, three hundred thirty-four".
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