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114204944330857 is a prime number
BaseRepresentation
bin11001111101111001101001…
…001000110111000001101001
3112222100212220221011012101201
4121331321221020313001221
5104432113211222041412
61042521005510044201
733025014661555522
oct3175715110670151
9488325827135351
10114204944330857
1133431054837a06
1210985824949661
134b95631856003
14202b797c91849
15d30aecc4de57
hex67de69237069

114204944330857 has 2 divisors, whose sum is σ = 114204944330858. Its totient is φ = 114204944330856.

The previous prime is 114204944330849. The next prime is 114204944330909. The reversal of 114204944330857 is 758033449402411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84766712989456 + 29438231341401 = 9206884^2 + 5425701^2 .

It is a cyclic number.

It is not a de Polignac number, because 114204944330857 - 23 = 114204944330849 is a prime.

It is a super-2 number, since 2×1142049443308572 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114204944330798 and 114204944330807.

It is not a weakly prime, because it can be changed into another prime (114204944330557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57102472165428 + 57102472165429.

It is an arithmetic number, because the mean of its divisors is an integer number (57102472165429).

Almost surely, 2114204944330857 is an apocalyptic number.

It is an amenable number.

114204944330857 is a deficient number, since it is larger than the sum of its proper divisors (1).

114204944330857 is an equidigital number, since it uses as much as digits as its factorization.

114204944330857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11612160, while the sum is 55.

The spelling of 114204944330857 in words is "one hundred fourteen trillion, two hundred four billion, nine hundred forty-four million, three hundred thirty thousand, eight hundred fifty-seven".