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11421152503 = 71413159931
BaseRepresentation
bin10101010001100000…
…01111010011110111
31002110221220122212021
422220300033103313
5141342303340003
65125150534011
7553012123465
oct125060172367
932427818767
1011421152503
114930a40a12
122268b07307
131100263b07
147a4bbd835
1546ca302bd
hex2a8c0f4f7

11421152503 has 4 divisors (see below), whose sum is σ = 11421383848. Its totient is φ = 11420921160.

The previous prime is 11421152497. The next prime is 11421152539. The reversal of 11421152503 is 30525112411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30525112411 = 57153459041.

It is a cyclic number.

It is not a de Polignac number, because 11421152503 - 29 = 11421151991 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11421152593) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8553 + ... + 151378.

It is an arithmetic number, because the mean of its divisors is an integer number (2855345962).

Almost surely, 211421152503 is an apocalyptic number.

11421152503 is a deficient number, since it is larger than the sum of its proper divisors (231345).

11421152503 is an equidigital number, since it uses as much as digits as its factorization.

11421152503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231344.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 11421152503 its reverse (30525112411), we get a palindrome (41946264914).

The spelling of 11421152503 in words is "eleven billion, four hundred twenty-one million, one hundred fifty-two thousand, five hundred three".

Divisors: 1 71413 159931 11421152503