Base | Representation |
---|---|
bin | 10000100111101101000… |
… | …110110010100000111011 |
3 | 11001012002000000201020011 |
4 | 100213231012302200323 |
5 | 122203102421012103 |
6 | 2232405512242351 |
7 | 145342254323632 |
oct | 20475506624073 |
9 | 4035060021204 |
10 | 1142144313403 |
11 | 400420764475 |
12 | 1654319a03b7 |
13 | 8391c192622 |
14 | 3d3cc778519 |
15 | 1ea9a854d6d |
hex | 109ed1b283b |
1142144313403 has 2 divisors, whose sum is σ = 1142144313404. Its totient is φ = 1142144313402.
The previous prime is 1142144313379. The next prime is 1142144313413. The reversal of 1142144313403 is 3043134412411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1142144313403 - 217 = 1142144182331 is a prime.
It is not a weakly prime, because it can be changed into another prime (1142144313413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571072156701 + 571072156702.
It is an arithmetic number, because the mean of its divisors is an integer number (571072156702).
Almost surely, 21142144313403 is an apocalyptic number.
1142144313403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142144313403 is an equidigital number, since it uses as much as digits as its factorization.
1142144313403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1142144313403 its reverse (3043134412411), we get a palindrome (4185278725814).
The spelling of 1142144313403 in words is "one trillion, one hundred forty-two billion, one hundred forty-four million, three hundred thirteen thousand, four hundred three".
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