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11422001031131 is a prime number
BaseRepresentation
bin1010011000110110010001…
…0100000110011111011011
31111102221011220001020020002
42212031210110012133123
52444114224230444011
640143110030123215
72256132555566255
oct246154424063733
944387156036202
1011422001031131
1137040528a1669
1213457b105050b
1364b122b857c2
142b6b836a6cd5
1514c1a4836c3b
hexa63645067db

11422001031131 has 2 divisors, whose sum is σ = 11422001031132. Its totient is φ = 11422001031130.

The previous prime is 11422001031097. The next prime is 11422001031137. The reversal of 11422001031131 is 13113010022411.

11422001031131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11422001031131 - 222 = 11421996836827 is a prime.

It is a super-2 number, since 2×114220010311312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11422001031137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711000515565 + 5711000515566.

It is an arithmetic number, because the mean of its divisors is an integer number (5711000515566).

Almost surely, 211422001031131 is an apocalyptic number.

11422001031131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11422001031131 is an equidigital number, since it uses as much as digits as its factorization.

11422001031131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11422001031131 its reverse (13113010022411), we get a palindrome (24535011053542).

The spelling of 11422001031131 in words is "eleven trillion, four hundred twenty-two billion, one million, thirty-one thousand, one hundred thirty-one".