Base | Representation |
---|---|
bin | 1010011000110110010110… |
… | …1100100110100100011001 |
3 | 1111102221020111200220201122 |
4 | 2212031211230212210121 |
5 | 2444114301200344233 |
6 | 40143112215255025 |
7 | 2256133260024032 |
oct | 246154554464431 |
9 | 44387214626648 |
10 | 11422024231193 |
11 | 37040649a8174 |
12 | 13457b897a475 |
13 | 64b127919654 |
14 | 2b6b867c5a89 |
15 | 14c1a68bad98 |
hex | a6365b26919 |
11422024231193 has 2 divisors, whose sum is σ = 11422024231194. Its totient is φ = 11422024231192.
The previous prime is 11422024231169. The next prime is 11422024231297. The reversal of 11422024231193 is 39113242022411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8185795932889 + 3236228298304 = 2861083^2 + 1798952^2 .
It is a cyclic number.
It is not a de Polignac number, because 11422024231193 - 26 = 11422024231129 is a prime.
It is not a weakly prime, because it can be changed into another prime (11422024231103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711012115596 + 5711012115597.
It is an arithmetic number, because the mean of its divisors is an integer number (5711012115597).
Almost surely, 211422024231193 is an apocalyptic number.
It is an amenable number.
11422024231193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11422024231193 is an equidigital number, since it uses as much as digits as its factorization.
11422024231193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 11422024231193 in words is "eleven trillion, four hundred twenty-two billion, twenty-four million, two hundred thirty-one thousand, one hundred ninety-three".
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