Base | Representation |
---|---|
bin | 11001111110011010010101… |
… | …111011011011000000000011 |
3 | 112222111020112220001110220221 |
4 | 121332122111323123000003 |
5 | 104433202113203140113 |
6 | 1042545053524443511 |
7 | 33030400034012266 |
oct | 3176322573330003 |
9 | 488436486043827 |
10 | 114240055521283 |
11 | 33444a32122a5a |
12 | 109905a3549597 |
13 | 4b98a38b0ab33 |
14 | 202d369062cdd |
15 | d319a544498d |
hex | 67e695edb003 |
114240055521283 has 2 divisors, whose sum is σ = 114240055521284. Its totient is φ = 114240055521282.
The previous prime is 114240055521161. The next prime is 114240055521289. The reversal of 114240055521283 is 382125550042411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114240055521283 - 237 = 114102616567811 is a prime.
It is not a weakly prime, because it can be changed into another prime (114240055521289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120027760641 + 57120027760642.
It is an arithmetic number, because the mean of its divisors is an integer number (57120027760642).
Almost surely, 2114240055521283 is an apocalyptic number.
114240055521283 is a deficient number, since it is larger than the sum of its proper divisors (1).
114240055521283 is an equidigital number, since it uses as much as digits as its factorization.
114240055521283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384000, while the sum is 43.
The spelling of 114240055521283 in words is "one hundred fourteen trillion, two hundred forty billion, fifty-five million, five hundred twenty-one thousand, two hundred eighty-three".
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