114240133045141 has 4 divisors (see below), whose sum is σ = 114357785088384. Its totient is φ = 114122481001900.

The previous prime is 114240133045121. The next prime is 114240133045177. The reversal of 114240133045141 is 141540331042411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114240133045141 - 2¹¹ = 114240133043093 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114240133045097 and 114240133045106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114240133045121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58826020165 + ... + 58826022106.

It is an arithmetic number, because the mean of its divisors is an integer number (28589446272096).

Almost surely, 2^{114240133045141} is an apocalyptic number.

It is an amenable number.

114240133045141 is a deficient number, since it is larger than the sum of its proper divisors (117652043243).

114240133045141 is an equidigital number, since it uses as much as digits as its factorization.

114240133045141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117652043242.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 114240133045141 its reverse (141540331042411), we get a palindrome (255780464087552).

The spelling of 114240133045141 in words is "one hundred fourteen trillion, two hundred forty billion, one hundred thirty-three million, forty-five thousand, one hundred forty-one".