Base | Representation |
---|---|
bin | 1010011000111101110011… |
… | …1010101001011000000011 |
3 | 1111110010101220101002110002 |
4 | 2212033130322221120003 |
5 | 2444132400221321121 |
6 | 40144042510030215 |
7 | 2256233655135056 |
oct | 246173472513003 |
9 | 44403356332402 |
10 | 11424024401411 |
11 | 37049a0a50706 |
12 | 13460767a836b |
13 | 64b38612331b |
14 | 2b6cd62c6a9d |
15 | 14c2722b3e0b |
hex | a63dcea9603 |
11424024401411 has 2 divisors, whose sum is σ = 11424024401412. Its totient is φ = 11424024401410.
The previous prime is 11424024401359. The next prime is 11424024401453. The reversal of 11424024401411 is 11410442042411.
11424024401411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11424024401411 - 210 = 11424024400387 is a prime.
It is not a weakly prime, because it can be changed into another prime (11424024401011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712012200705 + 5712012200706.
It is an arithmetic number, because the mean of its divisors is an integer number (5712012200706).
Almost surely, 211424024401411 is an apocalyptic number.
11424024401411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424024401411 is an equidigital number, since it uses as much as digits as its factorization.
11424024401411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4096, while the sum is 29.
Adding to 11424024401411 its reverse (11410442042411), we get a palindrome (22834466443822).
The spelling of 11424024401411 in words is "eleven trillion, four hundred twenty-four billion, twenty-four million, four hundred one thousand, four hundred eleven".
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