1142404133131 has 2 divisors, whose sum is σ = 1142404133132. Its totient is φ = 1142404133130.

The previous prime is 1142404133093. The next prime is 1142404133141. The reversal of 1142404133131 is 1313314042411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1142404133131 - 2¹¹ = 1142404131083 is a prime.

It is a super-2 number, since 2×1142404133131² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1142404133131.

It is not a weakly prime, because it can be changed into another prime (1142404133141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571202066565 + 571202066566.

It is an arithmetic number, because the mean of its divisors is an integer number (571202066566).

Almost surely, 2^{1142404133131} is an apocalyptic number.

1142404133131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142404133131 is an equidigital number, since it uses as much as digits as its factorization.

1142404133131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1142404133131 its reverse (1313314042411), we get a palindrome (2455718175542).

The spelling of 1142404133131 in words is "one trillion, one hundred forty-two billion, four hundred four million, one hundred thirty-three thousand, one hundred thirty-one".