Base | Representation |
---|---|
bin | 11001111110011100001010… |
… | …100110100111101100101011 |
3 | 112222111102121022101211101201 |
4 | 121332130022212213230223 |
5 | 104433220120312040124 |
6 | 1042550020052225031 |
7 | 33030466403225602 |
oct | 3176341246475453 |
9 | 488442538354351 |
10 | 114242013002539 |
11 | 33445847069664 |
12 | 10990a4b00b177 |
13 | 4b98c8b519076 |
14 | 202d4b3010a39 |
15 | d31a6c209144 |
hex | 67e70a9a7b2b |
114242013002539 has 2 divisors, whose sum is σ = 114242013002540. Its totient is φ = 114242013002538.
The previous prime is 114242013002527. The next prime is 114242013002549. The reversal of 114242013002539 is 935200310242411.
It is a strong prime.
It is an emirp because it is prime and its reverse (935200310242411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114242013002539 - 223 = 114242004613931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114242013002498 and 114242013002507.
It is not a weakly prime, because it can be changed into another prime (114242013002549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121006501269 + 57121006501270.
It is an arithmetic number, because the mean of its divisors is an integer number (57121006501270).
Almost surely, 2114242013002539 is an apocalyptic number.
114242013002539 is a deficient number, since it is larger than the sum of its proper divisors (1).
114242013002539 is an equidigital number, since it uses as much as digits as its factorization.
114242013002539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 114242013002539 in words is "one hundred fourteen trillion, two hundred forty-two billion, thirteen million, two thousand, five hundred thirty-nine".
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