1142421433 has 4 divisors (see below), whose sum is σ = 1166728320. Its totient is φ = 1118114548.

The previous prime is 1142421421. The next prime is 1142421439. The reversal of 1142421433 is 3341242411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3341242411 = 13 ⋅257018647.

It is a cyclic number.

It is not a de Polignac number, because 1142421433 - 2⁹ = 1142420921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1142421398 and 1142421407.

It is not an unprimeable number, because it can be changed into a prime (1142421439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12153373 + ... + 12153466.

It is an arithmetic number, because the mean of its divisors is an integer number (291682080).

Almost surely, 2^1142421433 is an apocalyptic number.

It is an amenable number.

1142421433 is a deficient number, since it is larger than the sum of its proper divisors (24306887).

1142421433 is an equidigital number, since it uses as much as digits as its factorization.

1142421433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24306886.

The product of its digits is 2304, while the sum is 25.

The square root of 1142421433 is about 33799.7253391207. The cubic root of 1142421433 is about 1045.3830339636.

Adding to 1142421433 its reverse (3341242411), we get a palindrome (4483663844).

The spelling of 1142421433 in words is "one billion, one hundred forty-two million, four hundred twenty-one thousand, four hundred thirty-three".