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114242201310073 is a prime number
BaseRepresentation
bin11001111110011100010101…
…110100111101001101111001
3112222111110002102201211202211
4121332130111310331031321
5104433221012013410243
61042550050500255121
733030504150634264
oct3176342564751571
9488443072654684
10114242201310073
1133445933395921
1210990aa20a14a1
134b98cbb53b345
14202d4d002bcdb
15d31a7da03d9d
hex67e715d3d379

114242201310073 has 2 divisors, whose sum is σ = 114242201310074. Its totient is φ = 114242201310072.

The previous prime is 114242201309969. The next prime is 114242201310077. The reversal of 114242201310073 is 370013102242411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113248694734569 + 993506575504 = 10641837^2 + 996748^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114242201310073 is a prime.

It is not a weakly prime, because it can be changed into another prime (114242201310077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121100655036 + 57121100655037.

It is an arithmetic number, because the mean of its divisors is an integer number (57121100655037).

Almost surely, 2114242201310073 is an apocalyptic number.

It is an amenable number.

114242201310073 is a deficient number, since it is larger than the sum of its proper divisors (1).

114242201310073 is an equidigital number, since it uses as much as digits as its factorization.

114242201310073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 114242201310073 its reverse (370013102242411), we get a palindrome (484255303552484).

The spelling of 114242201310073 in words is "one hundred fourteen trillion, two hundred forty-two billion, two hundred one million, three hundred ten thousand, seventy-three".