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114243200413 = 154699738487
BaseRepresentation
bin110101001100101101…
…1001110010110011101
3101220212210201220001221
41222121123032112131
53332432224403123
6124252124133341
711153024116066
oct1523133162635
9356783656057
10114243200413
11444a5343411
121a183997251
13aa08620094
14575a96356d
152e898ac25d
hex1a996ce59d

114243200413 has 4 divisors (see below), whose sum is σ = 114244093600. Its totient is φ = 114242307228.

The previous prime is 114243200389. The next prime is 114243200453. The reversal of 114243200413 is 314002342411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 114243200413 - 213 = 114243192221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114243200453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214545 + ... + 523942.

It is an arithmetic number, because the mean of its divisors is an integer number (28561023400).

Almost surely, 2114243200413 is an apocalyptic number.

It is an amenable number.

114243200413 is a deficient number, since it is larger than the sum of its proper divisors (893187).

114243200413 is an equidigital number, since it uses as much as digits as its factorization.

114243200413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 893186.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 114243200413 its reverse (314002342411), we get a palindrome (428245542824).

The spelling of 114243200413 in words is "one hundred fourteen billion, two hundred forty-three million, two hundred thousand, four hundred thirteen".

Divisors: 1 154699 738487 114243200413