Search a number
-
+
11424433213 = 13982190167
BaseRepresentation
bin10101010001111001…
…10000010000111101
31002111012002100011001
422220330300100331
5141344123330323
65125345130301
7553052036314
oct125074602075
932435070131
1011424433213
114932881846
12226a029991
131100b4216b
147a53d527b
1546ce7c3ad
hex2a8f3043d

11424433213 has 4 divisors (see below), whose sum is σ = 11506623520. Its totient is φ = 11342242908.

The previous prime is 11424433169. The next prime is 11424433253. The reversal of 11424433213 is 31233442411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11424433213 - 213 = 11424425021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11424433253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41094945 + ... + 41095222.

It is an arithmetic number, because the mean of its divisors is an integer number (2876655880).

Almost surely, 211424433213 is an apocalyptic number.

It is an amenable number.

11424433213 is a deficient number, since it is larger than the sum of its proper divisors (82190307).

11424433213 is an equidigital number, since it uses as much as digits as its factorization.

11424433213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82190306.

The product of its digits is 6912, while the sum is 28.

Adding to 11424433213 its reverse (31233442411), we get a palindrome (42657875624).

The spelling of 11424433213 in words is "eleven billion, four hundred twenty-four million, four hundred thirty-three thousand, two hundred thirteen".

Divisors: 1 139 82190167 11424433213