Base | Representation |
---|---|
bin | 10000101000000011000… |
… | …111010001110110010101 |
3 | 11001020000201210101120212 |
4 | 100220003013101312111 |
5 | 122204331431244001 |
6 | 2232510302135205 |
7 | 145354356600524 |
oct | 20500307216625 |
9 | 4036021711525 |
10 | 1142513540501 |
11 | 4005a0121233 |
12 | 165515581505 |
13 | 8397a81b1b8 |
14 | 3d42580c4bb |
15 | 1eabce8a7bb |
hex | 10a031d1d95 |
1142513540501 has 16 divisors (see below), whose sum is σ = 1228269331584. Its totient is φ = 1058831668224.
The previous prime is 1142513540489. The next prime is 1142513540507. The reversal of 1142513540501 is 1050453152411.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1142513540501 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1142513540507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2650541 + ... + 3051293.
It is an arithmetic number, because the mean of its divisors is an integer number (76766833224).
Almost surely, 21142513540501 is an apocalyptic number.
It is an amenable number.
1142513540501 is a deficient number, since it is larger than the sum of its proper divisors (85755791083).
1142513540501 is a wasteful number, since it uses less digits than its factorization.
1142513540501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 403340.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 1142513540501 its reverse (1050453152411), we get a palindrome (2192966692912).
The spelling of 1142513540501 in words is "one trillion, one hundred forty-two billion, five hundred thirteen million, five hundred forty thousand, five hundred one".
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