Base | Representation |
---|---|
bin | 11001111110100110111010… |
… | …010101100010101110100011 |
3 | 112222112112101102122112210211 |
4 | 121332212322111202232203 |
5 | 104433412233110002324 |
6 | 1042555205025034551 |
7 | 33031355336555164 |
oct | 3176467225425643 |
9 | 488475342575724 |
10 | 114253551250339 |
11 | 3344a728107a46 |
12 | 1099312b185a57 |
13 | 4b9a0a9aca927 |
14 | 202dc8959176b |
15 | d31ee5169294 |
hex | 67e9ba562ba3 |
114253551250339 has 2 divisors, whose sum is σ = 114253551250340. Its totient is φ = 114253551250338.
The previous prime is 114253551250297. The next prime is 114253551250429. The reversal of 114253551250339 is 933052155352411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114253551250339 - 27 = 114253551250211 is a prime.
It is a super-3 number, since 3×1142535512503393 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 114253551250292 and 114253551250301.
It is not a weakly prime, because it can be changed into another prime (114253551250639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57126775625169 + 57126775625170.
It is an arithmetic number, because the mean of its divisors is an integer number (57126775625170).
Almost surely, 2114253551250339 is an apocalyptic number.
114253551250339 is a deficient number, since it is larger than the sum of its proper divisors (1).
114253551250339 is an equidigital number, since it uses as much as digits as its factorization.
114253551250339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2430000, while the sum is 49.
The spelling of 114253551250339 in words is "one hundred fourteen trillion, two hundred fifty-three billion, five hundred fifty-one million, two hundred fifty thousand, three hundred thirty-nine".
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