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11425433 is a prime number
BaseRepresentation
bin101011100101…
…011010011001
3210111110202012
4223211122121
510411103213
61044515305
7166054205
oct53453231
923443665
1011425433
1164a4108
1239abb35
1324a0616
141735b05
15100a4a8
hexae5699

11425433 has 2 divisors, whose sum is σ = 11425434. Its totient is φ = 11425432.

The previous prime is 11425417. The next prime is 11425459. The reversal of 11425433 is 33452411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10004569 + 1420864 = 3163^2 + 1192^2 .

It is a cyclic number.

It is not a de Polignac number, because 11425433 - 24 = 11425417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11425399 and 11425408.

It is not a weakly prime, because it can be changed into another prime (11425493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712716 + 5712717.

It is an arithmetic number, because the mean of its divisors is an integer number (5712717).

Almost surely, 211425433 is an apocalyptic number.

It is an amenable number.

11425433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11425433 is an equidigital number, since it uses as much as digits as its factorization.

11425433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 23.

The square root of 11425433 is about 3380.1528071967. The cubic root of 11425433 is about 225.2289554180.

Adding to 11425433 its reverse (33452411), we get a palindrome (44877844).

The spelling of 11425433 in words is "eleven million, four hundred twenty-five thousand, four hundred thirty-three".