114255025333301 has 4 divisors (see below), whose sum is σ = 118194853793100. Its totient is φ = 110315196873504.

The previous prime is 114255025333247. The next prime is 114255025333307. The reversal of 114255025333301 is 103333520552411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 30733430163076 + 83521595170225 = 5543774^2 + 9139015^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114255025333301 is a prime.

It is a super-2 number, since 2×114255025333301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114255025333307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1969914229856 + ... + 1969914229913.

It is an arithmetic number, because the mean of its divisors is an integer number (29548713448275).

Almost surely, 2^{114255025333301} is an apocalyptic number.

It is an amenable number.

114255025333301 is a deficient number, since it is larger than the sum of its proper divisors (3939828459799).

114255025333301 is an equidigital number, since it uses as much as digits as its factorization.

114255025333301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3939828459798.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 114255025333301 its reverse (103333520552411), we get a palindrome (217588545885712).

The spelling of 114255025333301 in words is "one hundred fourteen trillion, two hundred fifty-five billion, twenty-five million, three hundred thirty-three thousand, three hundred one".