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114255033401147 is a prime number
BaseRepresentation
bin11001111110101000010010…
…101011011111111100111011
3112222112200012201120121111012
4121332220102223133330323
5104433423302022314042
61043000012052424135
733031440144622442
oct3176502253377473
9488480181517435
10114255033401147
1133450318806871
121099348361804b
134b9a284bb0742
14202dd8a369d59
15d32080339e82
hex67ea12adff3b

114255033401147 has 2 divisors, whose sum is σ = 114255033401148. Its totient is φ = 114255033401146.

The previous prime is 114255033401143. The next prime is 114255033401213. The reversal of 114255033401147 is 741104330552411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114255033401147 - 22 = 114255033401143 is a prime.

It is not a weakly prime, because it can be changed into another prime (114255033401141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127516700573 + 57127516700574.

It is an arithmetic number, because the mean of its divisors is an integer number (57127516700574).

Almost surely, 2114255033401147 is an apocalyptic number.

114255033401147 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255033401147 is an equidigital number, since it uses as much as digits as its factorization.

114255033401147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

Adding to 114255033401147 its reverse (741104330552411), we get a palindrome (855359363953558).

The spelling of 114255033401147 in words is "one hundred fourteen trillion, two hundred fifty-five billion, thirty-three million, four hundred one thousand, one hundred forty-seven".